x^3+2x^2+2sx+4=0

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Solution for x^3+2x^2+2sx+4=0 equation:


Simplifying
x3 + 2x2 + 2sx + 4 = 0

Reorder the terms:
4 + 2sx + 2x2 + x3 = 0

Solving
4 + 2sx + 2x2 + x3 = 0

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + 2sx + 2x2 + -4 + x3 = 0 + -4

Reorder the terms:
4 + -4 + 2sx + 2x2 + x3 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 2sx + 2x2 + x3 = 0 + -4
2sx + 2x2 + x3 = 0 + -4

Combine like terms: 0 + -4 = -4
2sx + 2x2 + x3 = -4

Add '-2x2' to each side of the equation.
2sx + 2x2 + -2x2 + x3 = -4 + -2x2

Combine like terms: 2x2 + -2x2 = 0
2sx + 0 + x3 = -4 + -2x2
2sx + x3 = -4 + -2x2

Add '-1x3' to each side of the equation.
2sx + x3 + -1x3 = -4 + -2x2 + -1x3

Combine like terms: x3 + -1x3 = 0
2sx + 0 = -4 + -2x2 + -1x3
2sx = -4 + -2x2 + -1x3

Divide each side by '2x'.
s = -2x-1 + -1x + -0.5x2

Simplifying
s = -2x-1 + -1x + -0.5x2

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